6.2 Flux across an LCSFrom the previous page, recall that
where here we have indicated the explicit functional dependencies of each variable. The derivative of L with time gives
For the spatial gradient of L we have,
However, since xq is the point on the LCS closest to point x, then the vector x - xq must be normal to the LCS, which implies that
because the closest point on the LCS, xq, does not change when the point x is varied in the direction normal to the curve. As an technical point, Eq. (18) is really only guaranteed to hold over an open neighborhood containing the LCS, within which each point x has a unique and well-defined xq. This open neighborhood, which we will denote , always exists because the LCS is a smooth curve, and hence its curvature is finite, implying that there always exists an open set around the LCS such that each x in this open set has a unique xq. That is, since there are no kinks or discontinuities on the LCS, there always exists an open set containing the LCS such that for any point , there is a unique point xq on the LCS which is closer to x than any other point on the LCS (for a more rigorous proof of the existence of see Shadden, et al (2005)). Plugging Eq. (18) into Eq. (17) gives,
where denotes a unit vector orthogonal to the LCS at time t. Similarly to above, we also have
So we can now rewrite Eq. (16) as
On the LCS, the two points x and xq are equal (and hence L=0); however, we can think of x as a Lagrangian, or material, point which is advected with the fluid, while xq is a point which moves with the LCS. Therefore when evaluated on the LCS, i.e along L=0, the right-hand side of Eq. (20) represents the difference in the velocity of the two points, projected in the direction normal to the LCS. This component of the difference in velocities is precisely what contributes to particles crossing the LCS. Therefore, the total flux across the LCS is given by
where s is some arc length parametrization variable. While Eq. (21) presents a concise expression for the flux, by itself it is no more useful than just writing the flux in terms of the right hand side of Eq. (20). Typically when studying a problem we are given the velocity field v, from which we obtain the FTLE field. Therefore, to compute the flux, we should determine
in terms of these two fields (or quantities directly measured from these fields). The following theorem provides such an expression:
where is a unit vector tangent to the LCS and J is the Jacobian derivative of the velocity field v and all terms on the right-hand side are evaluated along L = 0. The proof of this theorem is somewhat lengthy and will be covered on the next page, however, let us first interpret this result.
Most LCS of interest are well-defined, and thus the term (23) is sufficiently small such that the product of terms (23) and (25) is negligible. Additionally, we will see in the Examples that even for relatively short integration times T, ridges in the FTLE field are practically invariant manifolds, with flux measurements on the order of numerical error.
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Page created 04-15-2005, Last updated 04-15-05, Copyright © 2005, All Rights Reserved.